Evaluate 105 3 using suitable identity

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WebMar 31, 2024 · Transcript Ex 9.5, 6 Using identities, evaluate. (ix) 1.05×9.5 1.05×9.5 = 105/100×95/10 = (105 × 95)/1000 = ( (100 + 5) × (100 − 5))/1000 (𝑎+𝑏) (𝑎−𝑏)=𝑎^2−𝑏^2 Putting 𝑎 = 100 & 𝑏 = 5 = ( (100)^2 − (5)^2)/1000 = (10000 − 25)/1000 = 9975/1000 = 9.975 Next: Ex 9.5, 7 (i) → Ask a doubt Chapter 9 Class 8 Algebraic Expressions and Identities WebFind the following product by using suitable identity 102×104 A 10578 B 11508 C 10608 D 10218 Easy Solution Verified by Toppr Correct option is C) 102×104 =(100+2)×(100+4) Using, x 2+(a+b)x+ab =100 2+(2+4)100+2(4) =10000+600+8 =10608 Was this answer helpful? 0 0 Similar questions Find the product, using suitable properties …

Using a suitable identity evaluate \\[{(105)^2}\\]. - Vedantu

WebUsing the identities, evaluate the following: 8 1 2. Medium. View solution > Evaluate 1 0 2 2. Hard. View solution > Using the identities, evaluate the following: 1 0 5 2. Medium. View solution > View more. CLASSES AND TRENDING CHAPTER. class 5. The Fish Tale Across the Wall Tenths and Hundredths Parts and Whole Can you see the Pattern? WebUsing suitable identity, evaluate (−32) 3+(18) 3+(14) 3 Medium Solution Verified by Toppr Let a=−32,b=18,c=14 We see that a+b+c=−32+18+14=0 Now as we know that, If a+b+c=0 then a 3+b 3+c 3=3abc So (−32) 3+(18) 3+(14) 3=3(−32)(18)(14) ∴(−32) 3+(18) 3+(14) 3=−24192 Was this answer helpful? 0 0 Similar questions full wyoming map

Using identities, evaluate 95 × 105. - BYJU

WebEvaluate the following by using identities: 103×97 Medium Solution Verified by Toppr Correct option is A) 103×97=(100+3)(100−3) Using, a 2−b 2=(a+b)(a−b) =(100) 2−(3) 2 … WebApr 3, 2024 · The number inside the bracket is 105. We can break the number 105 as 105 = 100 + 5. Substitute the value of 105 = 100 + 5 in equation (1) ⇒ (105)3 = (100 + 5)3. … WebThis video explains the concept of Expansion using Algebraic Identities. All Questions Ask a Doubt Answered Unanswered My Questions My Answers Filter Questions CBSE 8 - Maths Draw and show (A+B) ² =A²+2 A B + B². Asked by muskaanmenuk 10 Jun, 2024, 08:59: PM ANSWERED BY EXPERT CBSE 8 - Maths full xl bed spreads

Evaluate using suitable identity a) 104 x 105 b) (98) 3

Evaluate the following using suitable identities: (i) (99)^3

WebEvaluate the following (using identities): 103×105 Easy Solution Verified by Toppr Correct option is A) Given, (103)(105) ⇒(104−1)(104+1). We know, a 2−b 2=(a+b)(a−b). Then, (103)(105) =(104−1)(104+1) =(104) 2−1 2 =10816−1 =10815. Therefore, the required answer is 10815. Was this answer helpful? 0 0 Similar questions WebSolution Verified by Toppr Given : (995) 2 we can Write (995) 2 as (995) 2=(1000−5) 2 According to the equation (a−b) 2=a 2−2ab+b 1 So we get, Using the formula we can it write it as (995) 2=(1000) 2−2(1000)(5)+(5) 2 On further calculation we get, (995) 2=100000−10000+25 (995) 2=990025 Was this answer helpful? 0 0 Find All solutions for … full xl fitted sheet setsWebExpand using suitable identity- 108×105 Easy Solution Verified by Toppr 108×105=(100+8)(100+5)=100 2+100(8+5)+8×5=10000+1300+40=11340 Was this answer helpful? 0 0 Similar questions Factorize the following using the Identities: x 2−64 Easy View solution > Factorize the following using the Identities: 49m 2−56m+16 Easy View … giocare a fortnite online

"WebMar 28, 2024 · Transcript. Ex 2.5, 7 Evaluate the following using suitable identities: (iii) (998)3 We write 998 = 1000 – 2 (998)3 = (1000 − 2)3 Using (a – b)3 = a3 – b3 – 3ab (a … " - Evaluate 105 3 using suitable identity

Evaluate 105 3 using suitable identity

WebUsing identities, evaluate 297 × 303 Question Using identities, evaluate 297×303 A 8999 B 899 C 89991 D 89990 Easy Solution Verified by Toppr Correct option is C) (297)(303) =(300−3)(300+3) Using , (a−b)(a+b)=a 2−b 2 we get, (300) 2−(3) 2 =90000−9 =89991 Was this answer helpful? 0 0 Similar questions Using the identities, evaluate the following: WebMar 21, 2024 · Q126 Evaluate (105)^3 using a suitable Identity Evaluate 105 3 Evaluate 105 whole cube - YouTube More Questions on Algebraic...

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WebAug 28, 2024 · Click here 👆 to get an answer to your question ️ evaluate 105 × 95 , using suitable identity. akshad53 akshad53 28.08.2024 Math Secondary School answered • expert verified ... Advertisement sakshii8080 sakshii8080 The given data in the above question, It is given that the value is (105 x 95) Have to evaluate the given value by … WebEvaluate the following using suitable identity. (105) 2 A 10025 B 11025 C 11125 D 12025 Medium Solution Verified by Toppr Correct option is B) (105) 2=(100+5) 2=100 2+5 2+2(100)(5) =10000+25+1000=11025 Was this answer helpful? 0 0 Similar questions Evaluate the following by using the identities: 103 2 Easy View solution >

WebThe correct option is B 9975. 95 can be written as 100 - 5 and 105 can be written as 100+ 5. 95×105=(100−5)×(100+5) which is in the form (a−b)(a+b) where a = 100 and b = 5. We … WebJun 29, 2024 · Solution : Write the expression as, Applying identity, Here, a=100 and b=3 Substitute the values, Therefore, Advertisement shaym1210 Dear your answer is (97)³ = (100-3)³ = 100³-3³-3*100*100*3 + 3*3*3*100 Using (a-b)³ = a³-b³-3a²b+3ab² = 912673 Hope it helps you Please Mark it as brainliest answer Advertisement

WebThe correct option is C 2756. 52×53 can be written as (50+2)(50+3) We know that, (x+a)(x+b) =x2+(a+b)x+ab, Here, x=50,a =2 and b =3. ∴ (50+2)(50+3) … WebDec 30, 2024 · Solve by using suitable identity 103×105 Advertisement Loved by our community 18 people found it helpful identity (x+a) (x+b)=x²+xb+ax+ab =x²+ (a+b)x+ab Mark any one as brainliest Advertisement Loved by our community 16 people found it helpful Brainly User 103×105 (100+3) (100+5) Identity (x+a) (x+b)=x^2+ (a+b)x+a×b = 100^2+ …

WebMar 24, 2024 · It is given that; \[{(105)^2}\] We have to evaluate the value of \[{(105)^2}\] by using suitable identity. With the help of the identities we can get any value quickly. An algebraic identity is an equality that holds for any values of its variables. \[105\] is close to 100. So, we can write it as \[105 = 100 + 5\] Now, we will apply the identity of

WebClick here👆to get an answer to your question ️ Evaluate the value of (101)^2 by using suitable identity. Solve Study Textbooks Guides. Join / Login >> Class 9 >> Maths >> Polynomials >> Algebraic Identities >> Evaluate the value of (101)^2 by using . ... Evaluate 3 3 × 2 7 using suitable identity. Medium. full xl cotton sheetsWebAug 3, 2024 · a) 104 ×105 (100+4)×(100+5) using identity (x+a) (x+b) = x square ( a+b ) x + ab , where x =100 , a =4 , b=5. (100 ) square +(4+5)(100)+(4×5) 10000 + (9) (100) + … full xl fitted bed sheetsWebNCERT Solutions Class 9 Maths Chapter 2 Exercise 2.5 Question 7:. Summary: The evaluated values of the following (99) 3, (102) 3, and (998) 3 using suitable identities are 970299, 1061208, and 994011992 respectively. giocare a mahjong gratisWebThe p660 form absorbs red light and is converted to the p73o form believed to induce a biological response. The P 7 3 0 form absorbs far-red and is converted to the inactive P 6 6 0 form. The P 7 3 0 form kept in the dark reverts to the P 6 6 0 form (Hendricks 1959). The action spectrum for photolability is seen in the lower part of Figure 9. giocare a age of empire onlineWebSolution: Using algebraic Identities, (x + a) (x + b) = x 2 + (a + b)x + ab (a + b) (a - b) = a 2 - b 2 (i) 103 × 107 Identity: (x + a) (x + b) = x 2 + (a + b)x + ab 103 × 107 = (100 + 3) (100 + 7) Substituting x = 100, a = 3, b = 7 in the above identity, we get = (100) 2 + (3 + 7) (100) + (3) (7) = 10000 + 1000 + 21 = 11021 (ii) 95 × 96 full xpath ieWebEvaluate by using suitable identity : 997^3 Question Evaluate by using suitable identity : 997 3 Medium Solution Verified by Toppr We have, (997) 3 ⇒(1000−3) 3 Since, (x−y) 3=x 3−y 3−3xy(x−y) Therefore, =(1000) 3−(3) 3−3×1000×3(1000−3) =1000000000−27−9000×(1000−3) =1000000000−27−9000000+27000 … giocare a burraco gratis onlineWebMar 22, 2024 · Transcript Example 17 Evaluate 105 × 106 without multiplying directly. 105 × 106 = (100 + 5) × (100 + 6) Using Identity (x + a) (x + b) = x2 + (a + b)x + ab, where x = 100 , a = 5, b= 6, = (100)2 + (5 + 6) (100) + (5 × 6) = 10000 + (11) (100) + 30 = 10000 + 1100+ 30 = 11130 Next: Example 18 (i) Important → Ask a doubt full xl mattress for adjustable bed